3-2x^2=6x

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Solution for 3-2x^2=6x equation:



3-2x^2=6x
We move all terms to the left:
3-2x^2-(6x)=0
a = -2; b = -6; c = +3;
Δ = b2-4ac
Δ = -62-4·(-2)·3
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{15}}{2*-2}=\frac{6-2\sqrt{15}}{-4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{15}}{2*-2}=\frac{6+2\sqrt{15}}{-4} $

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